12q^2+11qb-15b^2=0

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Solution for 12q^2+11qb-15b^2=0 equation:


Simplifying
12q2 + 11qb + -15b2 = 0

Reorder the terms:
11bq + -15b2 + 12q2 = 0

Solving
11bq + -15b2 + 12q2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-5b + -3q)(3b + -4q) = 0

Subproblem 1

Set the factor '(-5b + -3q)' equal to zero and attempt to solve: Simplifying -5b + -3q = 0 Solving -5b + -3q = 0 Move all terms containing b to the left, all other terms to the right. Add '3q' to each side of the equation. -5b + -3q + 3q = 0 + 3q Combine like terms: -3q + 3q = 0 -5b + 0 = 0 + 3q -5b = 0 + 3q Remove the zero: -5b = 3q Divide each side by '-5'. b = -0.6q Simplifying b = -0.6q

Subproblem 2

Set the factor '(3b + -4q)' equal to zero and attempt to solve: Simplifying 3b + -4q = 0 Solving 3b + -4q = 0 Move all terms containing b to the left, all other terms to the right. Add '4q' to each side of the equation. 3b + -4q + 4q = 0 + 4q Combine like terms: -4q + 4q = 0 3b + 0 = 0 + 4q 3b = 0 + 4q Remove the zero: 3b = 4q Divide each side by '3'. b = 1.333333333q Simplifying b = 1.333333333q

Solution

b = {-0.6q, 1.333333333q}

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